b^2-10b+1=-8

Solution for b^2-10b+1=-8 equation:

Simplifying
b2 + -10b + 1 = -8

Reorder the terms:
1 + -10b + b2 = -8

Solving
1 + -10b + b2 = -8

Solving for variable 'b'.

Reorder the terms:
1 + 8 + -10b + b2 = -8 + 8

Combine like terms: 1 + 8 = 9
9 + -10b + b2 = -8 + 8

Combine like terms: -8 + 8 = 0
9 + -10b + b2 = 0

Factor a trinomial.
(1 + -1b)(9 + -1b) = 0

Subproblem 1
Set the factor '(1 + -1b)' equal to zero and attempt to solve:

Simplifying
1 + -1b = 0

Solving
1 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1b = 0 + -1
-1b = 0 + -1

Combine like terms: 0 + -1 = -1
-1b = -1

Divide each side by '-1'.
b = 1

Simplifying
b = 1
Subproblem 2
Set the factor '(9 + -1b)' equal to zero and attempt to solve:

Simplifying
9 + -1b = 0

Solving
9 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -1b = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -1b = 0 + -9
-1b = 0 + -9

Combine like terms: 0 + -9 = -9
-1b = -9

Divide each side by '-1'.
b = 9

Simplifying
b = 9
Solution
b = {1, 9}